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Popular Calculus >

area y=sqrt(x),y=x^2

Solution

area

y = x, y = x^{2}

Solution

\frac{1}{3}

+1

Decimal

0.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} x - x^{2} d x

Solve

\int_{0}^{1} x - x^{2} d x : \frac{1}{3}

The area is:

= \frac{1}{3}

Graph

Popular Examples

integral of ((x^2))/(sqrt(2x-x^2))

\int \frac{( x ^{2} )}{2 x - x ^{2}} d x

derivative of f(x)=4sqrt(x)+6/(xsqrt(x))

d er i v a t i v e f (x) = 4 x + \frac{6}{x x}

integral of (2z)/(z^2+1)

\int \frac{2 z}{z ^{2} + 1} d z

(\partial)/(\partial s)(ln(rs^8t^8)+1)

\frac{\partial}{\partial s} (ln (r s^{8} t^{8}) + 1)

derivative of cos(sin(e^x))

d er i v a t i v e cos (sin (e^{x}))

Frequently Asked Questions (FAQ)

What is area y=sqrt(x),y=x^2 ?
The answer to area y=sqrt(x),y=x^2 is 1/3