What is the derivative of y=(6x^2-10x+1)^{-4} ?

The derivative of y=(6x^2-10x+1)^{-4} is -(4(12x-10))/((6x^2-10x+1)^5)

What is the first derivative of y=(6x^2-10x+1)^{-4} ?

The first derivative of y=(6x^2-10x+1)^{-4} is -(4(12x-10))/((6x^2-10x+1)^5)

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derivative of

y = (6 x^{2} - 10 x + 1)^{- 4}

- \frac{4 ( 12 x - 10 )}{( 6 x ^{2} - 10 x + 1 ) ^{5}}

Solution steps

\frac{d}{d x} ((6 x^{2} - 10 x + 1)^{- 4})

Apply the chain rule:

- \frac{4}{( 6 x ^{2} - 10 x + 1 ) ^{5}} \frac{d}{d x} (6 x^{2} - 10 x + 1)

= - \frac{4}{( 6 x ^{2} - 10 x + 1 ) ^{5}} \frac{d}{d x} (6 x^{2} - 10 x + 1)

\frac{d}{d x} (6 x^{2} - 10 x + 1) = 12 x - 10

= - \frac{4}{( 6 x ^{2} - 10 x + 1 ) ^{5}} (12 x - 10)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{4 ( 12 x - 10 )}{( 6 x ^{2} - 10 x + 1 ) ^{5}}

\int [\frac{( sin ( x ) )}{x}] d x

\frac{d y}{d x} + x y = 4 x

\frac{\partial}{\partial y} (25 - x^{2} - y^{2})

\frac{d}{d x} (arctan (8 x))

d er i v a t i v e y = (9 x)^{3 x}

What is the derivative of y=(6x^2-10x+1)^{-4} ?
The derivative of y=(6x^2-10x+1)^{-4} is -(4(12x-10))/((6x^2-10x+1)^5)
What is the first derivative of y=(6x^2-10x+1)^{-4} ?
The first derivative of y=(6x^2-10x+1)^{-4} is -(4(12x-10))/((6x^2-10x+1)^5)