(d^2}{dx^2}(-8sin(\frac{3x)/2+1))

解答

\frac{d ^{2}}{d x ^{2}} (- 8 sin (\frac{3 x}{2} + 1))

18 sin (\frac{3 x}{2} + 1)

求解步骤

\frac{d ^{2}}{d x ^{2}} (- 8 sin (\frac{3 x}{2} + 1))

\frac{d}{d x} (- 8 sin (\frac{3 x}{2} + 1)) = - 12 cos (\frac{3 x}{2} + 1)

= \frac{d}{d x} (- 12 cos (\frac{3 x}{2} + 1))

\frac{d}{d x} (- 12 cos (\frac{3 x}{2} + 1)) = 18 sin (\frac{3 x}{2} + 1)

= 18 sin (\frac{3 x}{2} + 1)

\frac{\partial}{\partial t} (x e^{- t} sin (θ))

x \to 0 + lim (\frac{1}{x ^{2}} + ln (x))

\int \frac{- 10}{x ^{2} ( 25 - x ^{2} ) ^{\frac{1}{2}}} d x

t an g e n t x (x - 8)

\int 4 x d x