integral from-2pi to 2pi of x^2sin(x)

解答

\int_{- 2 π}^{2 π} x^{2} sin (x) d x

0

求解步骤

\int_{- 2 π}^{2 π} x^{2} sin (x) d x

如果 f(x) 是奇函数，并且在区间:

[- a, a]

范围内连续，则

\int_{- a}^{a} f (x) d x = 0

x^{2} sin (x)

的奇偶性:

奇

= 0

\int sec (x) cos (x) d x

y^{^{'''}} + 9 y^{^{'}} = 0

t an g e n t f (x) = \frac{1}{1 - x}, at x = 2

\frac{d y}{d t} = y - 4 t + (y - 4 t)^{2} + 4

\int x (2 x^{2} + 1)^{5} d x