y^'-y^{(5/3)}=0

解

y^{^{'}} - y^{(\frac{5}{3})} = 0

y = - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}, y = - - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}

解答ステップ

y^{'} (t) - y^{(\frac{5}{3})} = 0

分離可能 ODE を解く:

y = - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}, y = - - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}

y = - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}, y = - - \frac{27}{8 t ^{3} + 24 c _{1} t ^{2} + 24 c _{1}^{2} t + 8 c _{1}^{3}}