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tangent y=sqrt(9-6x),\at x=-1

解答

切线

y = 9 - 6 x, at x = - 1

解答

y = - \frac{3}{5} x + 15 - \frac{3}{5}

求解步骤

找到切点:

(- 1, 15)

计算

y = 9 - 6 x

的斜率:

\frac{d y}{d x} = - \frac{3}{9 - 6 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{5}

找到斜率 m=

- \frac{3}{5}

且穿过

(- 1, 15)

的直线:

y = - \frac{3}{5} x + 15 - \frac{3}{5}

y = - \frac{3}{5} x + 15 - \frac{3}{5}

作图

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