y^'-1/x y=9,y(1)= 1/7

解答

y^{^{'}} - \frac{1}{x} y = 9, y (1) = \frac{1}{7}

y = 9 x ln (x) + \frac{x}{7}

求解步骤

y^{'} (x) - \frac{1}{x} y = 9

求解线性方程:

y = 9 x ln (x) + \frac{x}{7}

y = 9 x ln (x) + \frac{x}{7}

\int \frac{1}{( 1 + \frac{x}{2} ) ^{2}} d x

\frac{d}{d x} (x^{3} - 5 x)

\frac{d}{d x} ((1 - x) (x^{2} - 2)^{2})

x \to - 1 + lim (\frac{5}{x + 1})

d er i v a t i v e f (x) = x^{5} e^{x}