What is the derivative of 12x^3+6x^2+2x ?

The derivative of 12x^3+6x^2+2x is 36x^2+12x+2

What is the first derivative of 12x^3+6x^2+2x ?

The first derivative of 12x^3+6x^2+2x is 36x^2+12x+2

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\frac{d}{d x} (12 x^{3} + 6 x^{2} + 2 x)

36 x^{2} + 12 x + 2

Solution steps

\frac{d}{d x} (12 x^{3} + 6 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12 x^{3}) + \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (12 x^{3}) = 36 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (2 x) = 2

= 36 x^{2} + 12 x + 2

d er i v a t i v e f (x) = 3 x^{2} + 2

in v erse l a pl a ce \frac{7}{s ^{4}}

\int x tan^{3} (x^{2}) d x

y^{^{''}} + 6 y^{^{'}} + 6 y = 0

y^{^{'}} = 2 t, y (0) = 1

What is the derivative of 12x^3+6x^2+2x ?
The derivative of 12x^3+6x^2+2x is 36x^2+12x+2
What is the first derivative of 12x^3+6x^2+2x ?
The first derivative of 12x^3+6x^2+2x is 36x^2+12x+2