limit as x approaches 3+of ln|x^2-9|

Lösung

x \to 3 + lim (ln x^{2} - 9)

- \infty

Schritte zur Lösung

x \to 3 + lim (ln x^{2} - 9)

x^{2} - 9

ist positiv wenn

x \to 3 +

. Deshalb

x^{2} - 9 = x^{2} - 9

= x \to 3 + lim (ln (x^{2} - 9))

Wende die Kettenregel für Grenzen an:

- \infty

= - \infty

\frac{d ^{3}}{d x ^{3}} (6 x + 8)

l a pl a ce t r an s f or m (1 - e^{t} + 3 e^{- 4 t}) cos (5 t)

\int \frac{x sin ( x ) + cos ( x ) - 1}{x ^{2}} d x

\frac{\partial}{\partial x} (ln (x^{2} + 3 x y + 2 y^{2}))

7 x^{2} y + \frac{d y}{d x} = 4 x^{2}