What is the integral from 2 to infinity of e^{-5p} ?

The integral from 2 to infinity of e^{-5p} is 1/(5e^{10)}

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integral from 2 to infinity of e^{-5p}

\int_{2}^{\infty} e^{- 5 p} d p

\frac{1}{5 e ^{10}}

Decimal

9.07999 E - 6

Solution steps

\int_{2}^{\infty} e^{- 5 p} d p

Compute the indefinite integral:

\int e^{- 5 p} d p = - \frac{1}{5} e^{- 5 p} + C

Compute the boundaries:

\int_{2}^{\infty} e^{- 5 p} d p = 0 - (- \frac{1}{5 e ^{10}})

= 0 - (- \frac{1}{5 e ^{10}})

Simplify

= \frac{1}{5 e ^{10}}

\int_{1}^{2} \frac{7}{x ^{3} + 5 x} d x

\int x cos^{2} (6 x) d x

x ln (x) y^{^{'}} + y = 8 x e^{x}

t a y l or \frac{x}{1 - x ^{2}}

n = 0 \sum \infty \frac{1}{n ln ( n )}

What is the integral from 2 to infinity of e^{-5p} ?
The integral from 2 to infinity of e^{-5p} is 1/(5e^{10)}