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tangent g(x)=ln(x^2),(e,2)

解答

切线

g (x) = ln (x^{2}), (e, 2)

解答

y = \frac{2}{e} x

求解步骤

计算

g (x) = ln (x^{2})

的斜率:

\frac{d g ( x )}{d x} = \frac{2}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{e}

找到斜率 m=

\frac{2}{e}

且穿过

(e, 2)

的直线:

y = \frac{2}{e} x

y = \frac{2}{e} x

作图

流行的例子

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\int_{0}^{8} t + 2 t^{3} d t

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s l o p e (8.2) (- 10.4)

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\int \frac{x + 2}{x ^{2} - 4 x} d x

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