y^{''}+y^'-2y=2t,y(0)=0,y^'(0)=4

Lösung

y^{^{''}} + y^{^{'}} - 2 y = 2 t, y (0) = 0, y^{^{'}} (0) = 4

y = (\frac{3}{2} + \frac{1}{2}) e^{t} - \frac{3}{2} e^{- 2 t} - t - \frac{1}{2}

Schritte zur Lösung

y^{''} (t) + y^{'} (t) - 2 y = 2 t

Solve linear ODE:

y = (\frac{3}{2} + \frac{1}{2}) e^{t} - \frac{3}{2} e^{- 2 t} - t - \frac{1}{2}

y = (\frac{3}{2} + \frac{1}{2}) e^{t} - \frac{3}{2} e^{- 2 t} - t - \frac{1}{2}

\frac{\partial}{\partial x} (sin (x) cosh (y))

\frac{d y}{d x} = 1 + x + y + x \cdot y

x \to \infty lim ((1 + \frac{5}{x})^{\frac{x}{7}})

\int \frac{2000}{5 x + 10} d x

in v erse l a pl a ce \frac{( s + 2 )}{( s ^{2} + s + 1 )}