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integral of (x^3)/(x^2+x+1)

Lösung

\int \frac{x ^{3}}{x ^{2} + x + 1} d x

\frac{1}{2} x^{2} - x + \frac{2}{3} arctan (\frac{2 x + 1}{3}) + \frac{1}{8} - \frac{3}{4} + C

Schritte zur Lösung

\int \frac{x ^{3}}{x ^{2} + x + 1} d x

Vervollständige das Quadrat

x^{2} + x + 1 : (x + \frac{1}{2})^{2} + \frac{3}{4}

= \int \frac{x ^{3}}{( x + \frac{1}{2} ) ^{2} + \frac{3}{4}} d x

Wende U-Substitution an

= \int \frac{( 2 u - 1 ) ^{3}}{2 ( 4 u ^{2} + 3 )} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{( 2 u - 1 ) ^{3}}{4 u ^{2} + 3} d u

Wende U-Substitution an

= \frac{1}{2} \cdot \int \frac{v ^{3}}{2 ( v ^{2} + 2 v + 4 )} d v

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int \frac{v ^{3}}{v ^{2} + 2 v + 4} d v

Vervollständige das Quadrat

v^{2} + 2 v + 4 : (v + 1)^{2} + 3

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int \frac{v ^{3}}{( v + 1 ) ^{2} + 3} d v

Wende U-Substitution an

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int \frac{( w - 1 ) ^{3}}{w ^{2} + 3} d w

Lange Division

\frac{( w - 1 ) ^{3}}{w ^{2} + 3} : w - 3 + \frac{8}{w ^{2} + 3}

= \frac{1}{2} \cdot \frac{1}{2} \cdot \int w - 3 + \frac{8}{w ^{2} + 3} d w

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} \cdot \frac{1}{2} (\int w d w - \int 3 d w + \int \frac{8}{w ^{2} + 3} d w)

\int w d w = \frac{w ^{2}}{2}

\int 3 d w = 3 w

\int \frac{8}{w ^{2} + 3} d w = \frac{8}{3} arctan (\frac{w}{3})

= \frac{1}{2} \cdot \frac{1}{2} (\frac{w ^{2}}{2} - 3 w + \frac{8}{3} arctan (\frac{w}{3}))

Ersetze zurück

= \frac{1}{2} \cdot \frac{1}{2} (\frac{( 2 ( x + \frac{1}{2} ) - 1 + 1 ) ^{2}}{2} - 3 (2 (x + \frac{1}{2}) - 1 + 1) + \frac{8}{3} arctan (\frac{2 ( x + \frac{1}{2} ) - 1 + 1}{3}))

Vereinfache

\frac{1}{2} \cdot \frac{1}{2} (\frac{( 2 ( x + \frac{1}{2} ) - 1 + 1 ) ^{2}}{2} - 3 (2 (x + \frac{1}{2}) - 1 + 1) + \frac{8}{3} arctan (\frac{2 ( x + \frac{1}{2} ) - 1 + 1}{3})) : \frac{1}{2} x^{2} - x + \frac{2}{3} arctan (\frac{2 x + 1}{3}) + \frac{1}{8} - \frac{3}{4}

= \frac{1}{2} x^{2} - x + \frac{2}{3} arctan (\frac{2 x + 1}{3}) + \frac{1}{8} - \frac{3}{4}

Füge eine Konstante zur Lösung hinzu

= \frac{1}{2} x^{2} - x + \frac{2}{3} arctan (\frac{2 x + 1}{3}) + \frac{1}{8} - \frac{3}{4} + C

y^{^{''}} + 9 y = 30 sin (t)

d er i v a t i v e f (x) = e^{x} x

\frac{\partial}{\partial x} (x \cdot y^{2} \cdot e^{z})

d er i v a t i v e y = cos^{3} (π t - 16)

t an g e n t f (x) = x^{4} + 2 x^{2} - x, (1, 2)