What is (\partial)/(\partial y)(-e^{-x}sin(y)) ?

The answer to (\partial)/(\partial y)(-e^{-x}sin(y)) is -e^{-x}cos(y)

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(\partial)/(\partial y)(-e^{-x}sin(y))

\frac{\partial}{\partial y} (- e^{- x} sin (y))

- e^{- x} cos (y)

Solution steps

\frac{\partial}{\partial y} (- e^{- x} sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - e^{- x} \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= - e^{- x} cos (y)

x \to 1 lim (x - 1)

\int sec^{2} (x) + sec (2 x) tan (2 x) d x

d er i v a t i v e p (θ) = 7 θ

f (x) = ln (x + 4)

\int \frac{1}{2 sin ( x ) - 3 cos ( x ) - 5} d x

What is (\partial)/(\partial y)(-e^{-x}sin(y)) ?
The answer to (\partial)/(\partial y)(-e^{-x}sin(y)) is -e^{-x}cos(y)