derivative of 2x^2+3x-2

Lösung

\frac{d}{d x} (2 x^{2} + 3 x - 2)

4 x + 3

Schritte zur Lösung

\frac{d}{d x} (2 x^{2} + 3 x - 2)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 4 x + 3 - 0

Vereinfache

= 4 x + 3

\frac{d}{d x} (5 x^{e})

\int 3 x e^{5 x} d x

\frac{d}{d x} (\frac{( x ^{2} - 4 x )}{x + 1})

\frac{d}{d x} (\frac{sin ( x ) + cos ( x )}{cos ( x )})

\frac{\partial}{\partial x} (sin (y^{2}) + 6 e^{x})