derivative of sqrt(3x^2-4x+2)

Lösung

\frac{d}{d x} (3 x^{2} - 4 x + 2)

\frac{3 x - 2}{3 x ^{2} - 4 x + 2}

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} - 4 x + 2)

Wende die Kettenregel an:

\frac{1}{2 3 x ^{2} - 4 x + 2} \frac{d}{d x} (3 x^{2} - 4 x + 2)

= \frac{1}{2 3 x ^{2} - 4 x + 2} \frac{d}{d x} (3 x^{2} - 4 x + 2)

\frac{d}{d x} (3 x^{2} - 4 x + 2) = 6 x - 4

= \frac{1}{2 3 x ^{2} - 4 x + 2} (6 x - 4)

Vereinfache

\frac{1}{2 3 x ^{2} - 4 x + 2} (6 x - 4) : \frac{3 x - 2}{3 x ^{2} - 4 x + 2}

= \frac{3 x - 2}{3 x ^{2} - 4 x + 2}

\frac{d y}{d x} + y = e^{6 x}

\frac{d}{d x} (cos^{2} (sin (2 x)))

\frac{d}{d x} ((x^{2} + 1)^{l n (x)})

i = 1 \sum \infty 4 (2)^{i - 1}

\int \frac{ln ( x ) - 2}{x ln ( x ) ( ln ( x ) - 1 )} d x