What is the tangent of f(x)=x^2-3x+6,\at x=2 ?

The tangent of f(x)=x^2-3x+6,\at x=2 is y=x+2

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tangent of f(x)=x^2-3x+6,\at x=2

tangent of

f (x) = x^{2} - 3 x + 6, at x = 2

y = x + 2

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

f (x) = x^{2} - 3 x + 6 : \frac{df ( x )}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, 4) : y = x + 2

y = x + 2

7 x^{2}, x^{2} + 4

x \to \infty lim (x - x)

\int_{0}^{1} x^{3} (2 x^{4} + 1)^{2} d x

\int \frac{cos ^{2} ( x )}{x} d x

\frac{d ^{3}}{d x ^{3}} (\frac{2}{x})

What is the tangent of f(x)=x^2-3x+6,\at x=2 ?
The tangent of f(x)=x^2-3x+6,\at x=2 is y=x+2