What is area 20+x-x^2,x^2-5x,[4,8] ?

The answer to area 20+x-x^2,x^2-5x,[4,8] is 262/3

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area 20+x-x^2,x^2-5x,[4,8]

area

20 + x - x^{2}, x^{2} - 5 x, [4, 8]

\frac{262}{3}

Decimal

87.33333 \dots

Solution steps

Apply the area formula:

\int_{4}^{8} 20 + x - x^{2} - (x^{2} - 5 x) d x

Solve

\int_{4}^{8} 20 + x - x^{2} - (x^{2} - 5 x) d x : \frac{262}{3}

The area is:

= \frac{262}{3}

e^{c o s^{2} (π t - 11)}

\frac{d}{d x} (x cos (π x))

\int_{- 5}^{5} \frac{1}{x ^{\frac{2}{3}}} d x

- arcsin (\frac{1}{4} x) + \frac{x}{16 - x ^{2}} + C

\int (x + 1) x^{2} + 2 x + 2 d x

What is area 20+x-x^2,x^2-5x,[4,8] ?
The answer to area 20+x-x^2,x^2-5x,[4,8] is 262/3