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Popular >

y^'+y=b

Solution

y^{^{'}} + y = b

Solution

y = - e^{- t - c_{1}} + b

Solution steps

y^{'} (t) + y = b

Solve separable ODE:

y = - e^{- t - c_{1}} + b

y = - e^{- t - c_{1}} + b

Graph

Popular Examples

derivative of sqrt(x)+2 derivative of

x + 2

(d^2)/(dx^2)(((1-2x))/(1+2x))

\frac{d ^{2}}{d x ^{2}} (\frac{( 1 - 2 x )}{1 + 2 x})

derivative of 2-sqrt(x)

\frac{d}{d x} (2 - x)

integral of 2/(x^3-x)

\int \frac{2}{x ^{3} - x} d x

inverse oflaplace s/((s^2+16)(s^2+9))inverse laplace

\frac{s}{( s ^{2} + 16 ) ( s ^{2} + 9 )}

Frequently Asked Questions (FAQ)

What is the solution for y^'+y=b ?
The solution for y^'+y=b is y=-e^{-t-c_{1}}+b