What is the integral of x/(sqrt(x-3)) ?

The integral of x/(sqrt(x-3)) is 2(1/3 (x-3)^{3/2}+3sqrt(x-3))+C

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integral of x/(sqrt(x-3))

\int \frac{x}{x - 3} d x

2 (\frac{1}{3} (x - 3)^{\frac{3}{2}} + 3 x - 3) + C

Solution steps

\int \frac{x}{x - 3} d x

Apply u-substitution

= \int 2 (u^{2} + 3) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int u^{2} + 3 d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{2} d u + \int 3 d u)

\int u^{2} d u = \frac{u ^{3}}{3}

\int 3 d u = 3 u

= 2 (\frac{u ^{3}}{3} + 3 u)

Substitute back

u = x - 3

= 2 (\frac{( x - 3 ) ^{3}}{3} + 3 x - 3)

Simplify

2 (\frac{( x - 3 ) ^{3}}{3} + 3 x - 3) : 2 (\frac{1}{3} (x - 3)^{\frac{3}{2}} + 3 x - 3)

= 2 (\frac{1}{3} (x - 3)^{\frac{3}{2}} + 3 x - 3)

Add a constant to the solution

= 2 (\frac{1}{3} (x - 3)^{\frac{3}{2}} + 3 x - 3) + C

\int \frac{1}{2} cos (x) d x

\frac{d}{d x} (\frac{3 x}{x ^{3} + 7 x - 5})

f (x) = lo g_{2} (1 - 3 x)

sin (2 x + π)

y^{^{''}} + 4 y^{^{'}} + 3 y = 4 e^{x}, y (0) = 0, y^{^{'}} (0) = 2

What is the integral of x/(sqrt(x-3)) ?
The integral of x/(sqrt(x-3)) is 2(1/3 (x-3)^{3/2}+3sqrt(x-3))+C