What is the derivative of y=(x^2+3x)2 ?

The derivative of y=(x^2+3x)2 is 2(2x+3)

What is the first derivative of y=(x^2+3x)2 ?

The first derivative of y=(x^2+3x)2 is 2(2x+3)

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derivative of

y = (x^{2} + 3 x) 2

2 (2 x + 3)

Solution steps

\frac{d}{d x} ((x^{2} + 3 x) \cdot 2)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 2 (2 x + 3)

\frac{\partial}{\partial x} (5 x^{2} + y^{2} + 9)

\int (cos^{2} (θ))^{2} d θ

\frac{\partial}{\partial x} (e^{- 6 t} (x + 3 t))

\frac{d ^{2}}{d x ^{2}} (\frac{4 x ^{3} + 6}{x})

\frac{s}{s ^{2} - 4 s + 5}

What is the derivative of y=(x^2+3x)2 ?
The derivative of y=(x^2+3x)2 is 2(2x+3)
What is the first derivative of y=(x^2+3x)2 ?
The first derivative of y=(x^2+3x)2 is 2(2x+3)