integral of x^2-4x+3

Lösung

\int x^{2} - 4 x + 3 d x

\frac{x ^{3}}{3} - 2 x^{2} + 3 x + C

Schritte zur Lösung

\int x^{2} - 4 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x - \int 4 x d x + \int 3 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 3 d x = 3 x

= \frac{x ^{3}}{3} - 2 x^{2} + 3 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} - 2 x^{2} + 3 x + C

d er i v a t i v e \frac{1}{2} x^{2} 49 - x^{2}

\int cos^{5} (x) sin (2 x) d x

\frac{\partial}{\partial x} (x^{2} - 2 x y + 6 y^{2} + x - 5 y)

\int y^{5} d y

x \to 0 lim (\frac{e ^{x} + 1}{x})