(\partial)/(\partial x)(ln(2x-y))

解答

\frac{\partial}{\partial x} (ln (2 x - y))

\frac{2}{2 x - y}

求解步骤

\frac{\partial}{\partial x} (ln (2 x - y))

将

y

视为常数

使用连锁律:

\frac{1}{2 x - y} \frac{\partial}{\partial x} (2 x - y)

= \frac{1}{2 x - y} \frac{\partial}{\partial x} (2 x - y)

\frac{\partial}{\partial x} (2 x - y) = 2

= \frac{1}{2 x - y} \cdot 2

化简

\frac{1}{2 x - y} \cdot 2 : \frac{2}{2 x - y}

= \frac{2}{2 x - y}

\int_{0}^{9} 9 + 3 x d x

d er i v a t i v e 3 t^{2}

y^{^{''}} - 4 y^{^{'}} + 53 y = 5 e^{2 t} cos (7 t)

d er i v a t i v e cos^{10} (sin (7 x))

y = 4 x (3 x - 2)^{5}