What is the integral from 0 to 1 of 6 ?

The integral from 0 to 1 of 6 is 6

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integral from 0 to 1 of 6

\int_{0}^{1} 6

6

Solution steps

\int_{0}^{1} 6 d x

Integral of a constant:

\int a d x = a x

= [6 x]_{0}^{1}

Compute the boundaries:

6

= 6

\frac{\partial}{\partial x} (x z - 5 x^{2} y^{3} z^{4})

\frac{\partial}{\partial x} (\frac{3 x - 2 y}{x ^{2} + 3 y})

\int \frac{cos ( x )}{sin ^{2} ( x ) - 36} d x

y^{^{''}} + 2 y^{^{'}} + 122 y = 0

\frac{\partial}{\partial x} (sin (- e^{y}))