(dy)/(dt)+2y=te^{-2t}

Lösung

\frac{d y}{d t} + 2 y = t e^{- 2 t}

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

Schritte zur Lösung

\frac{d y}{d t} + 2 y = t e^{- 2 t}

Solve linear ODE:

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

y = \frac{t ^{2}}{2 e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

\frac{\partial}{\partial x} (- 3 e^{x} ln (y))

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