(\partial)/(\partial x)(e^{xy}+x+y)

Lösung

\frac{\partial}{\partial x} (e^{x y} + x + y)

e^{x y} y + 1

Schritte zur Lösung

\frac{\partial}{\partial x} (e^{x y} + x + y)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x y}) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (e^{x y}) = e^{x y} y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= e^{x y} y + 1 + 0

Vereinfache

= e^{x y} y + 1

\frac{d x}{d y} = \frac{x ^{2} y ^{2}}{1 + x}

\int_{0}^{2} \frac{t}{( 3 - t ) ^{2}} d t

d er i v a t i v e - 1.2 (9) + 36

\int \frac{x}{x ^{2} + x} d x

\int \frac{1 + x}{1 - x} d x