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Beliebt Rechnen >

integral of 6sin^4(x)cos^2(x)

Lösung

\int 6 sin^{4} (x) cos^{2} (x) d x

Lösung

\frac{9}{4} x - \frac{1}{4} sin^{3} (x) cos (x) - \frac{9}{8} sin (2 x) + sin^{5} (x) cos (x) - \frac{15}{16} (2 x - sin (2 x)) + C

Schritte zur Lösung

\int 6 sin^{4} (x) cos^{2} (x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int sin^{4} (x) cos^{2} (x) d x

Umschreiben mit Hilfe von Trigonometrie-Identitäten

= 6 \cdot \int sin^{4} (x) (1 - sin^{2} (x)) d x

Multipliziere aus

sin^{4} (x) (1 - sin^{2} (x)) : sin^{4} (x) - sin^{6} (x)

= 6 \cdot \int sin^{4} (x) - sin^{6} (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 6 (\int sin^{4} (x) d x - \int sin^{6} (x) d x)

\int sin^{4} (x) d x = - \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x))

\int sin^{6} (x) d x = - \frac{cos ( x ) sin ^{5} ( x )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)))

= 6 (- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)) - (- \frac{cos ( x ) sin ^{5} ( x )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)))))

Vereinfache

6 (- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x)) - (- \frac{cos ( x ) sin ^{5} ( x )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (x) cos (x) + \frac{3}{8} (x - \frac{1}{2} sin (2 x))))) : \frac{9}{4} x - \frac{1}{4} sin^{3} (x) cos (x) - \frac{9}{8} sin (2 x) + sin^{5} (x) cos (x) - \frac{15}{16} (2 x - sin (2 x))

= \frac{9}{4} x - \frac{1}{4} sin^{3} (x) cos (x) - \frac{9}{8} sin (2 x) + sin^{5} (x) cos (x) - \frac{15}{16} (2 x - sin (2 x))

Füge eine Konstante zur Lösung hinzu

= \frac{9}{4} x - \frac{1}{4} sin^{3} (x) cos (x) - \frac{9}{8} sin (2 x) + sin^{5} (x) cos (x) - \frac{15}{16} (2 x - sin (2 x)) + C

Graph

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