24y^{''}-2y^'-15y=0

Lösung

24 y^{^{''}} - 2 y^{^{'}} - 15 y = 0

y = c_{1} e^{\frac{5 t}{6}} + c_{2} e^{- \frac{3 t}{4}}

Schritte zur Lösung

24 y^{''} (t) - 2 y^{'} (t) - 15 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{5 t}{6}} + c_{2} e^{- \frac{3 t}{4}}

y = c_{1} e^{\frac{5 t}{6}} + c_{2} e^{- \frac{3 t}{4}}

\frac{d}{d t} (cos^{2} (e^{c o s^{2} (t)}))

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