(sqrt(x+1))^'

Lösung

(x + 1)^{^{'}}

\frac{1}{2 x + 1}

Schritte zur Lösung

(x + 1)^{'}

Wende die Kettenregel an:

\frac{1}{2 x + 1} (x + 1)^{'}

= \frac{1}{2 x + 1} (x + 1)^{'}

(x + 1)^{'} = 1

= \frac{1}{2 x + 1} \cdot 1

Vereinfache

= \frac{1}{2 x + 1}

\frac{d}{d x} (\frac{6 x}{1 - cot ( x )})

x \to + 0 lim (\frac{e ^{x} - 1}{2 x})

x \to 0 lim (x (11 + \frac{7}{x}))

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