What is the derivative of 6e^x+4/(\sqrt[3]{x}) ?

The derivative of 6e^x+4/(\sqrt[3]{x}) is 6e^x-4/(3x^{4/3)}

What is the first derivative of 6e^x+4/(\sqrt[3]{x}) ?

The first derivative of 6e^x+4/(\sqrt[3]{x}) is 6e^x-4/(3x^{4/3)}

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\frac{d}{d x} (6 e^{x} + \frac{4}{3 x})

6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (6 e^{x} + \frac{4}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x}) + \frac{d}{d x} (\frac{4}{3 x})

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

\frac{d}{d x} (\frac{4}{3 x}) = - \frac{4}{3 x ^{\frac{4}{3}}}

= 6 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

x \to 5 lim (\frac{1}{x ^{2} - 1})

\frac{d}{d x} (\frac{2 x ^{2} + 8 x + 4}{x})

y^{^{''}} + 31 y = 0

\frac{d}{d x} (- 8 x^{\frac{1}{2}})

5 x + 6, at x = 6

What is the derivative of 6e^x+4/(\sqrt[3]{x}) ?
The derivative of 6e^x+4/(\sqrt[3]{x}) is 6e^x-4/(3x^{4/3)}
What is the first derivative of 6e^x+4/(\sqrt[3]{x}) ?
The first derivative of 6e^x+4/(\sqrt[3]{x}) is 6e^x-4/(3x^{4/3)}