What is the integral from-14 to 7 of (7e^x) ?

The integral from-14 to 7 of (7e^x) is 7(e^7-1/(e^{14)})

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integral from-14 to 7 of (7e^x)

\int_{- 14}^{7} (7 e^{x}) d x

7 (e^{7} - \frac{1}{e ^{14}})

Decimal

7676.43210 \dots

Solution steps

\int_{- 14}^{7} 7 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{- 14}^{7} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 7 [e^{x}]_{- 14}^{7}

Compute the boundaries:

e^{7} - \frac{1}{e ^{14}}

= 7 (e^{7} - \frac{1}{e ^{14}})

\int_{0}^{3} (3 x^{2} - 4 x + 1) d x

\frac{d}{d x} (x sin (\frac{y}{x}))

\frac{\partial}{\partial x} (cos (x) cos (y) e^{z})

\int \frac{1}{( x - 7 ) ^{2}} d x

y^{^{''}} - 5 y^{^{'}} - 6 y = 12 e^{2 t}

What is the integral from-14 to 7 of (7e^x) ?
The integral from-14 to 7 of (7e^x) is 7(e^7-1/(e^{14)})