What is the derivative of ln(3-x^2) ?

The derivative of ln(3-x^2) is -(2x)/(3-x^2)

What is the first derivative of ln(3-x^2) ?

The first derivative of ln(3-x^2) is -(2x)/(3-x^2)

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\frac{d}{d x} (ln (3 - x^{2}))

- \frac{2 x}{3 - x ^{2}}

Solution steps

\frac{d}{d x} (ln (3 - x^{2}))

Apply the chain rule:

\frac{1}{3 - x ^{2}} \frac{d}{d x} (3 - x^{2})

= \frac{1}{3 - x ^{2}} \frac{d}{d x} (3 - x^{2})

\frac{d}{d x} (3 - x^{2}) = - 2 x

= \frac{1}{3 - x ^{2}} (- 2 x)

Simplify

\frac{1}{3 - x ^{2}} (- 2 x) : - \frac{2 x}{3 - x ^{2}}

= - \frac{2 x}{3 - x ^{2}}

\frac{d}{d x} (24 + x^{2})

\frac{d}{d x} (e^{\frac{- 1}{x}})

x \to 0 lim (1 0^{x})

x \to 3 lim (\frac{x ^{2} - 2}{3 - x})

t an g e n t y = (x^{3} - 4 x)^{10}

What is the derivative of ln(3-x^2) ?
The derivative of ln(3-x^2) is -(2x)/(3-x^2)
What is the first derivative of ln(3-x^2) ?
The first derivative of ln(3-x^2) is -(2x)/(3-x^2)