What is the integral from 0 to pi of cos(x+pi) ?

The integral from 0 to pi of cos(x+pi) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to pi of cos(x+pi)

\int_{0}^{π} cos (x + π) d x

0

Solution steps

\int_{0}^{π} cos (x + π) d x

Rewrite using trig identities

= \int_{0}^{π} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{0}^{π}

Compute the boundaries:

0

= - 0

Simplify

= 0

\int \frac{x ^{2}}{x} d x

\frac{\partial}{\partial x} (3 a x^{2} + e^{xx} + e^{x})

\int x^{2} - 4 x + 1 d x

\frac{d}{d x} (\frac{5 x - x ^{2}}{x} - 3 cot (x))

\int (\frac{( y + 1 )}{y})^{2} d y

What is the integral from 0 to pi of cos(x+pi) ?
The integral from 0 to pi of cos(x+pi) is 0