What is the limit as x approaches 0 of cos(x^2+x) ?

The limit as x approaches 0 of cos(x^2+x) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

limit as x approaches 0 of cos(x^2+x)

x \to 0 lim (cos (x^{2} + x))

1

Solution steps

x \to 0 lim (cos (x^{2} + x))

Plug in the value

x = 0

= cos (0^{2} + 0)

Simplify

cos (0^{2} + 0) : 1

= 1

\int \frac{1 - x ^{2}}{x} d x

\frac{\partial}{\partial x} (- 9 e^{x} cos (yz))

\int x^{4} ln (x) d x

\int \frac{x ^{2} + 2 x + 3}{( x ^{2} + 16 ) ^{2}} d x

d er i v a t i v e sec^{3} (x)

What is the limit as x approaches 0 of cos(x^2+x) ?
The limit as x approaches 0 of cos(x^2+x) is 1