What is the tangent of f(x)=(e^x)/(x^2),\at x=1 ?

The tangent of f(x)=(e^x)/(x^2),\at x=1 is y=-ex+2e

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tangent of f(x)=(e^x)/(x^2),\at x=1

tangent of

f (x) = \frac{e ^{x}}{x ^{2}}, at x = 1

y = - e x + 2 e

Solution steps

Find the tangent point:

(1, e)

Find the slope of

f (x) = \frac{e ^{x}}{x ^{2}} : \frac{df ( x )}{d x} = \frac{e ^{x} ( x - 2 )}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - e

Find the line with slope m=

- e

and passing through

(1, e) : y = - e x + 2 e

y = - e x + 2 e

n = 1 \sum \infty \frac{3}{5 ^{n}}

\int \frac{3 x ^{5}}{1 - 12 x ^{6}} d x

\int 9 x e^{- x^{2}} d x

\int ln (x + 5) d x

\int_{0}^{1} \frac{4}{( x + 1 ) ( x ^{2} + 1 )} d x

What is the tangent of f(x)=(e^x)/(x^2),\at x=1 ?
The tangent of f(x)=(e^x)/(x^2),\at x=1 is y=-ex+2e