What is the derivative of (2x-1^3) ?

The derivative of (2x-1^3) is 6(2x-1)^2

What is the first derivative of (2x-1^3) ?

The first derivative of (2x-1^3) is 6(2x-1)^2

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\frac{d}{d x} ((2 x - 1)^{3})

6 (2 x - 1)^{2}

Solution steps

\frac{d}{d x} ((2 x - 1)^{3})

Apply the chain rule:

3 (2 x - 1)^{2} \frac{d}{d x} (2 x - 1)

= 3 (2 x - 1)^{2} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 3 (2 x - 1)^{2} \cdot 2

Simplify

= 6 (2 x - 1)^{2}

t an g e n t f (x) = \frac{1}{5 x}, at x = 9

a re a \frac{36}{9 + x ^{2}}, 1

\frac{d}{d x} (3 x - 2 y)

\int_{1}^{e} \frac{ln ( 2 x )}{x} d x

\frac{d}{d t} (cos^{3} (3 t^{2}))

What is the derivative of (2x-1^3) ?
The derivative of (2x-1^3) is 6(2x-1)^2
What is the first derivative of (2x-1^3) ?
The first derivative of (2x-1^3) is 6(2x-1)^2