10x-6ysqrt(x^2+1)y^'=0

Lösung

10 x - 6 y x^{2} + 1 y^{^{'}} = 0

y = \frac{10}{3} x^{2} + 1 + c_{1}, y = - \frac{10}{3} x^{2} + 1 + c_{1}

Schritte zur Lösung

10 x - 6 y x^{2} + 1 y^{'} (x) = 0

Solve separable ODE:

y = \frac{10}{3} x^{2} + 1 + c_{1}, y = - \frac{10}{3} x^{2} + 1 + c_{1}

y = \frac{10}{3} x^{2} + 1 + c_{1}, y = - \frac{10}{3} x^{2} + 1 + c_{1}

x \to 0 lim (\frac{3 - cos ( x )}{x})

d er i v a t i v e y = 3 cos^{2} (x)

\int \frac{1}{5} d x

\int cos (x) 16 - sin^{2} (x) d x

\frac{d}{d x} (- 20 sin (20 x) + cos (x))