(dx)/(dt)=1+t-x-tx

解答

\frac{d x}{d t} = 1 + t - x - t x

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

求解步骤

\frac{d x}{d t} = 1 + t - x - t x

求解可分离方程:

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

\int 2 (2 x + 4)^{5} d x

\frac{d}{d x} (4^{4})

d er i v a t i v e f (x) = (4 - x) (\frac{2}{x ^{2}} - 3)

t an g e n t y = - e^{- x - 2}, (- 3, - e)

\frac{\partial}{\partial v} (v)