(3x^2-2xy)dx+(2y-x^2)dy=0

解

(3 x^{2} - 2 x y) d x + (2 y - x^{2}) d y = 0

y = \frac{x ^{2} + x ^{4} - 4 ( x ^{3} - c _{1} )}{2}, y = \frac{x ^{2} - x ^{4} - 4 ( x ^{3} - c _{1} )}{2}

解答ステップ

(3 x^{2} - 2 x y) d x + (2 y - x^{2}) d y = 0

完全 ODE を解く:

y = \frac{x ^{2} + x ^{4} - 4 ( x ^{3} - c _{1} )}{2}, y = \frac{x ^{2} - x ^{4} - 4 ( x ^{3} - c _{1} )}{2}

y = \frac{x ^{2} + x ^{4} - 4 ( x ^{3} - c _{1} )}{2}, y = \frac{x ^{2} - x ^{4} - 4 ( x ^{3} - c _{1} )}{2}