6y^{''}+31y=0

Lösung

6 y^{^{''}} + 31 y = 0

y = c_{1} cos (\frac{31}{6} t) + c_{2} sin (\frac{31}{6} t)

Schritte zur Lösung

6 y^{''} (t) + 31 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{31}{6} t) + c_{2} sin (\frac{31}{6} t)

y = c_{1} cos (\frac{31}{6} t) + c_{2} sin (\frac{31}{6} t)

x \to 4 lim (\frac{x ^{3} - 6}{x - 4})

x \to - 3 lim (\frac{x}{x - 3})

d er i v a t i v e f (x) = - 6 x^{3}

x \to 1 lim (\frac{6 x ^{2} + 12 x - 18}{2 x - 2})

\int_{- 1}^{2} \frac{2}{( 2 x + 4 ) ^{3}} d x