(dy)/(dt)= 1/((y+1)(t-2)),y(0)=0

解答

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}, y (0) = 0

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

求解步骤

\frac{d y}{d t} = \frac{1}{( y + 1 ) ( t - 2 )}

求解线性方程:

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

y = - 1 + 2 ln (- \frac{t}{2} + 1) + 1

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