What is (\partial}{\partial x}(\frac{(2pi*l^2))/x) ?

The answer to (\partial}{\partial x}(\frac{(2pi*l^2))/x) is -(2pil^2)/(x^2)

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(\partial}{\partial x}(\frac{(2pi*l^2))/x)

\frac{\partial}{\partial x} (\frac{( 2 π \cdot l ^{2} )}{x})

- \frac{2 π l ^{2}}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{( 2 π l ^{2} )}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 π l^{2} \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 π l^{2} \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 π l^{2} (- 1 \cdot x^{- 1 - 1})

Simplify

2 π l^{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{2 π l ^{2}}{x ^{2}}

= - \frac{2 π l ^{2}}{x ^{2}}

\int_{0}^{16} x d x

\int_{0}^{4} 4 y^{2} - \frac{y ^{4}}{4} d y

x \to a lim (f (x) + g (x))

f (t) = cos (2 t)

x y \frac{d y}{d x} = 1

What is (\partial}{\partial x}(\frac{(2pi*l^2))/x) ?
The answer to (\partial}{\partial x}(\frac{(2pi*l^2))/x) is -(2pil^2)/(x^2)