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Beliebt Rechnen >

(\partial)/(\partial l)(9l^{2/3}k^{1/3})

Lösung

\frac{\partial}{\partial l} (9 l^{\frac{2}{3}} k^{\frac{1}{3}})

Lösung

\frac{6 k ^{\frac{1}{3}}}{l ^{\frac{1}{3}}}

Schritte zur Lösung

\frac{\partial}{\partial l} (9 l^{\frac{2}{3}} k^{\frac{1}{3}})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 k^{\frac{1}{3}} \frac{\partial}{\partial l} (l^{\frac{2}{3}})

Wende die Potenzregel an:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 k^{\frac{1}{3}} \frac{2}{3} l^{\frac{2}{3} - 1}

Vereinfache

9 k^{\frac{1}{3}} \frac{2}{3} l^{\frac{2}{3} - 1} : \frac{6 k ^{\frac{1}{3}}}{l ^{\frac{1}{3}}}

= \frac{6 k ^{\frac{1}{3}}}{l ^{\frac{1}{3}}}

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y^{''}+9y=24sin(3t)

y^{^{''}} + 9 y = 24 sin (3 t)

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y^'=(ln(2))/7 y-20,y(0)=200

y^{^{'}} = \frac{ln ( 2 )}{7} y - 20, y (0) = 200