derivative of sqrt(2x+3y)

Lösung

\frac{d}{d x} (2 x + 3 y)

\frac{2 + 3 \frac{d y}{d x}}{2 2 x + 3 y}

Schritte zur Lösung

\frac{d}{d x} (2 x + 3 y)

Wende die Kettenregel an:

\frac{1}{2 2 x + 3 y} \frac{d}{d x} (2 x + 3 y)

= \frac{1}{2 2 x + 3 y} \frac{d}{d x} (2 x + 3 y)

\frac{d}{d x} (2 x + 3 y) = 2 + 3 \frac{d y}{d x}

= \frac{1}{2 2 x + 3 y} (2 + 3 \frac{d y}{d x})

Vereinfache

\frac{1}{2 2 x + 3 y} (2 + 3 \frac{d y}{d x}) : \frac{2 + 3 \frac{d y}{d x}}{2 2 x + 3 y}

= \frac{2 + 3 \frac{d y}{d x}}{2 2 x + 3 y}

x \to 2 π lim (\frac{sin ( x )}{x})

\frac{\partial}{\partial y} (x ln (x y))

n = 1 \sum \infty \frac{cos ( nπ )}{n}

t \to 0 lim (\frac{e ^{- 1 t} - 1}{t})

im pl i c i t \frac{d y}{d x}, - \frac{x}{y} = 0