What is the ((cos(x))/(sin(x)))^' ?

The ((cos(x))/(sin(x)))^' is -csc^2(x)

What is the first ((cos(x))/(sin(x)))^' ?

The first ((cos(x))/(sin(x)))^' is -csc^2(x)

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(\frac{cos ( x )}{sin ( x )})^{^{'}}

- csc^{2} (x)

Solution steps

(\frac{cos ( x )}{sin ( x )})^{'}

Simplify

\frac{cos ( x )}{sin ( x )} : cot (x)

= (cot (x))^{^{'}}

Apply the common derivative:

(cot (x))^{'} = - csc^{2} (x)

= - csc^{2} (x)

\frac{d}{d x} (∣ x - 3 ∣)

t an g e n t y = sin (3 x) + sin^{2} (3 x), (0, 0)

x \to \infty lim (2, x)

\frac{\partial}{\partial x} (6 x^{2} + 9 x y + 5 y^{2})

((1 + sin (x))^{2} + (1 + cos (x))^{4})^{^{'}}

What is the ((cos(x))/(sin(x)))^' ?
The ((cos(x))/(sin(x)))^' is -csc^2(x)
What is the first ((cos(x))/(sin(x)))^' ?
The first ((cos(x))/(sin(x)))^' is -csc^2(x)