What is the solution for (dy)/(dt)=4t-0.1yt ?

The solution for (dy)/(dt)=4t-0.1yt is y=e^{-(t^2)/(20)+c_{1}}*10+40

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(dy)/(dt)=4t-0.1yt

\frac{d y}{d t} = 4 t - 0.1 y t

y = e^{- \frac{t ^{2}}{20} + c_{1}} \cdot 10 + 40

Solution steps

\frac{d y}{d t} = 4 t - 0.1 y t

Solve separable ODE:

y = e^{- \frac{t ^{2}}{20} + c_{1}} \cdot 10 + 40

y = e^{- \frac{t ^{2}}{20} + c_{1}} \cdot 10 + 40

d er i v a t i v e x^{2} - 5 x + 1

d er i v a t i v e - \frac{2 x ^{2}}{5 y ^{2}}

\int \frac{( x - 1 ) e ^{x}}{x ^{2}} d x

\frac{\partial}{\partial x} (cos (8 y - 3 x))

\frac{d}{d x} (\frac{1}{2} (cos (5 x))^{2})

What is the solution for (dy)/(dt)=4t-0.1yt ?
The solution for (dy)/(dt)=4t-0.1yt is y=e^{-(t^2)/(20)+c_{1}}*10+40