(\partial)/(\partial x)(4sin(2x))

Lösung

\frac{\partial}{\partial x} (4 sin (2 x))

8 cos (2 x)

Schritte zur Lösung

\frac{\partial}{\partial x} (4 sin (2 x))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial x} (sin (2 x))

Wende die Kettenregel an:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= 4 cos (2 x) \cdot 2

Vereinfache

= 8 cos (2 x)

\int \frac{1}{x ^{3} - 64} d x

(\frac{π}{x})^{^{'}}

\frac{\partial}{\partial h} (\frac{π}{3} h^{2} (3 r - h))

\frac{d}{d x} (cos (x - 7 x^{2}))

\int \frac{2 x}{x ^{3} + 1} d x