What is (\partial)/(\partial y)(2y^3) ?

The answer to (\partial)/(\partial y)(2y^3) is 6y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial y)(2y^3)

\frac{\partial}{\partial y} (2 y^{3})

6 y^{2}

Solution steps

\frac{\partial}{\partial y} (2 y^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (y^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 y^{3 - 1}

Simplify

= 6 y^{2}

\int \frac{16 x ^{2}}{( x - 24 ) ( x + 8 ) ^{2}} d x

\frac{\partial}{\partial y} (\frac{x + 1}{y - 1})

\int_{0}^{1} \frac{1}{x ( 1 + x )} d x

\int y y + 1 d y

d er i v a t i v e 4 tan^{2} (3 x)

What is (\partial)/(\partial y)(2y^3) ?
The answer to (\partial)/(\partial y)(2y^3) is 6y^2