What is the derivative of f(x)= 3/(sqrt(x)) ?

The derivative of f(x)= 3/(sqrt(x)) is -3/(2x^{3/2)}

What is the first derivative of f(x)= 3/(sqrt(x)) ?

The first derivative of f(x)= 3/(sqrt(x)) is -3/(2x^{3/2)}

derivative of

f (x) = \frac{3}{x}

- \frac{3}{2 x ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{3}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- \frac{1}{2} x^{- \frac{1}{2} - 1})

Simplify

3 (- \frac{1}{2} x^{- \frac{1}{2} - 1}) : - \frac{3}{2 x ^{\frac{3}{2}}}

= - \frac{3}{2 x ^{\frac{3}{2}}}

\frac{d}{d x} (\frac{π ( 9 x ^{2} + 6 x + 1 )}{36 x})

d er i v a t i v e tan^{9} (x)

x \to 2 - lim (\frac{x + 1}{4 - x ^{2}})

\int 3 - t^{2} d t

d er i v a t i v e f (t) = \frac{2 t + 1}{t + 3}

What is the derivative of f(x)= 3/(sqrt(x)) ?
The derivative of f(x)= 3/(sqrt(x)) is -3/(2x^{3/2)}
What is the first derivative of f(x)= 3/(sqrt(x)) ?
The first derivative of f(x)= 3/(sqrt(x)) is -3/(2x^{3/2)}