What is the limit as x approaches 0 of 1/(sqrt(x+1)) ?

The limit as x approaches 0 of 1/(sqrt(x+1)) is 1

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limit as x approaches 0 of 1/(sqrt(x+1))

x \to 0 lim (\frac{1}{x + 1})

1

Solution steps

x \to 0 lim (\frac{1}{x + 1})

Plug in the value

x = 0

= \frac{1}{0 + 1}

Simplify

= 1

\int (\frac{1}{3}) x^{3} - 5 x d x

\int (6 x^{2} - 4 x + 5) d x

\int \frac{1}{x ^{3} + 9 x} d x

t an g e n t 5 sec (x), at x = \frac{π}{3}

a re a - x^{2} + 3 x, 2 x^{3} - x^{2} - 5 x

What is the limit as x approaches 0 of 1/(sqrt(x+1)) ?
The limit as x approaches 0 of 1/(sqrt(x+1)) is 1